Final answer:
Without the graph showing the current variation over time, it's not possible to calculate the current at t=1.5 s and t=2.5 s using Faraday's Law and Ohm's Law. Additional information is needed to perform these calculations.
Step-by-step explanation:
To find the current in the loop at a specific time, we need to use Faraday's Law of Electromagnetic Induction, which states that an electromotive force (EMF) is induced in a circuit due to a change in magnetic flux through the loop. The induced EMF (ε) can be calculated using the formula ε = -N ∂Φ/∂t, where N is the number of turns in the loop, and ∂Φ/∂t is the rate of change of magnetic flux. Once the EMF has been calculated, we can determine the induced current (I) in the loop using Ohm's Law, where I = ε/R and R is the resistance of the loop.
However, without the graph that shows how the current varies with time, we cannot calculate the current for the specified times of t=1.5 s and t=2.5 s. Assuming we had this data, we would identify the rate of change of current at these specific times, calculate the rate of change of magnetic flux, find the induced EMF, and then calculate the current in the external loop.