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(x + 1)(x+3)(x + 5) ​

User Anaa
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1 Answer

3 votes

Answer:

x³ + 9x² + 23x + 15

Explanation:

(x + 1)(x + 3)(x + 5) ← expand the second/third factors using FOIL

= (x + 1)(x² + 8x + 15)

each term in the second factor is multiplied by each term in the first factor, that is

x(x² + 8x + 15) + 1 (x² + 8x + 15) ← distribute parenthesis

= x³ + 8x² + 15x + x² + 8x + 15 ← collect like terms

= x³ + 9x² + 23x + 15

User Antagony
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