Question

A boy start at A and walks 3km east to B.

He then walks 4km north to C.
Find the distance and bearing of Cfrom A.

Answer 1

The distance from A to C is 5 km

Explanation:

If you draw out the path the boy walks, it creates a right triangle, with 3 km and 4 km as the base and height and the hypotenuse as the unknown distance from A to C. Using the pythagoream
`a^(2) + b^(2) = c^(2)` , we can solve for c by filling in the a and b (the base and height)

`3^(2)` +
`4^(2)` =
`c^(2)`

9 + 16 =
`c^(2)`

25 =
`c^(2)`

`√(25) = \sqrt{c^(2) }`

5 = c