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A boy start at A and walks 3km east to B.

He then walks 4km north to C.
Find the distance and bearing of Cfrom A.

User BartoNaz
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1 Answer

2 votes

Answer:

The distance from A to C is 5 km

Explanation:

If you draw out the path the boy walks, it creates a right triangle, with 3 km and 4 km as the base and height and the hypotenuse as the unknown distance from A to C. Using the pythagoream
a^(2) + b^(2) = c^(2) , we can solve for c by filling in the a and b (the base and height)


3^(2) +
4^(2) =
c^(2)

9 + 16 =
c^(2)

25 =
c^(2)


√(25) = \sqrt{c^(2) }

5 = c

User Cheesemacfly
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