Answer:
There is no maximum value.
Step-by-step explanation:
1) The graph is an upward opening parabola; there is no maximum.
2) limx→∞(x2+2x+3)=∞, so there is no maximum.
Using y=f(x),3)
f'(x)=2x+2=0 at x=−1 . Therefore, −1
is the only critical number and the first or second derivative test will show that f(−1) is a minimum, not a maximum.