Answer:
11 and (11/16)
Explanation:
5(9)/(16)-2(1)/(2)+6(3)/(4)
Lets assume that the problem is asking us to take 5 (9/16) [5 and 9/16], subtract 2 and (1/2) and then add 6 and (3/4).
Lets convert all the numbers into fractions with common denominators.
1) 5 (9/16) = (80/16) + (9/16) = (89/16)
2) -2 (1/2) = - [(4/2)+(1/2)] = -(5/2)
3) +6 (3)/(4) = [(24/4)+(3/4) = (27/4)
Add these together:
(89/16) - (5/2) + (27/4)
Convert the fractions so that they have a common denominator. It looks like a denominator of 16 will work:
(89/16) - (8/8)*(5/2) + (4/4)*(27/4)
(89/16) - (10/16) + (108/16) = (197/16)
16 will go into 197 11 times, with 11 left over.
(197/16) is the same as 11 and (11/16)