Question

Please help me please please

Answer 1

first option

Explanation:

using the sine and cosine ratios in the right triangle and the exact values

sin60° =
`(√(3) )/(2)` and cos60° =
`(1)/(2)`

then

sin60° =
`(opposite)/(hypotenuse)` =
`(x)/(7)` =
`(√(3) )/(2)` ( cross- multiply )

2x = 7
`√(3)` ( divide both sides by 2 )

x =
`(7√(3) )/(2)`

and

cos60° =
`(adjacent)/(hypotenuse)` =
`(y)/(7)` =
`(1)/(2)` ( cross- multiply )

2y = 7 ( divide both sides by 2 )

y =
`(7)/(2)`