Question

What is the concentration of a solution if 45.0 ml of 1.50 mol/L

NaOH (aq) is diluted to a new volume of 175 m

Answer 1

The concentration of the solution after dilution is approximately 0.386 mol/L.

Step-by-step explanation:

To determine the concentration of the solution after dilution, we can use the formula:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given:

Initial concentration (C1) = 1.50 mol/L

Initial volume (V1) = 45.0 mL = 0.045 L

Final volume (V2) = 175 mL = 0.175 L

Let's substitute these values into the formula:

(1.50 mol/L)(0.045 L) = C2(0.175 L)

0.0675 mol = C2(0.175 L)

Now, we can solve for C2:

C2 = 0.0675 mol / 0.175 L

C2 ≈ 0.386 mol/L

Thus, the concentration of the solution after dilution is approximately 0.386 mol/L.