Question

Find the equation of the tangent line to the curve y3 −
xy2 +sin xy =1 at the point(0,1).

Answer 1

Answer: 5x-2=3

Explanation:

Given curve is y=3x

2

−x+1

dx

dy

​

=6x−1, differentiate the curve

So slope of tangent at (1,3) is, m=

dx

dy

​

∣

∣

∣

∣

∣

​

(1,3)

​

=6(1)−1=5

Hence equation of tangent passes through (1,3) is given by

y−3=5(x−1)

⇒y−3=5x−5

⇒5x−y=2