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58- 10x< 20 + 9x ....

User J Brand
by
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2 Answers

3 votes

Hello!


\sf 58 - 10x < 20 + 9x\\\\58 - 20 < 9x + 10x\\\\38 < 19x\\\\(38)/(19) < (19x)/(19) \\\\ 2 < x\\\\\boxed{\sf x > 2}

so the interval of this inequation is:

x ∈ ]2 ; +∞[

User Ytropek
by
8.3k points
7 votes

Answer:

x > 2

Explanation:

58 - 10x < 20 + 9x ( subtract 9x from both sides )

58 - 19x < 20 ( subtract 58 from both sides )

- 19x < - 38

divide both sides by - 19, reversing the symbol as a result of dividing by a negative quantity.

x > 2

User Kds
by
8.3k points

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