Question

PLS HELP!!!

In triangle △ABC, ∠C is a right angle and CD is the altitude to AB. Find the angles in △CBD and △CAD if m∠A = 65°
m∠DBC =
m∠DCB =
m∠CDB =
m∠ACD =
m∠ADC =

Answer 1

hope this helps

Explanation:

mDBC=25(alternate interior angles because ADC is 25 as well)

mDCB=90

mCDB=65

mACD=90(both angles have to equal 180 because it is a straight angle, so 180-90=90)

mADC=25