Question

88.00 mL of a concentrated ethanol solution is added to a container to make 1.50 L of a 0.36 M diluted solution. What was the initial concentration of the ethanol?

Answer 1

6.14 M

Step-by-step explanation:

C1V1 = C2V2

C1 * 0.088 L = 0.36 M * 1.50 L

C1 * 0.088 = 0.54

C1 = 0.54 / 0.088

C1 ≈ 6.14 M

Therefore, the initial concentration of the ethanol solution was approximately 6.14 M.