Question

Based on historical data, your manager believes that 29% of the company's orders come from first-time customers. A random sample of 88 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.34?

Answer 1

0.1515

Explanation:

`\displaystyle z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}=\frac{0.34-0.29}{\sqrt{(0.29(0.71))/(88)}}\approx1.03`

`P(Z > 1.03)=1-P(Z < 1.03)=1-0.8485=0.1515`