61.4k views
3 votes
What is the molarity of a 0.25 L solution containing 12 g of NaOH? Select the correct answer below: 1.2 M 8.6 M 3.4 M 2.8 M

User Halsdunes
by
8.1k points

1 Answer

3 votes

Required Answer:

  • the molarity of the solution is 1.2 M

Step-by-step explanation:

We are given with,

  • Volume of Solution= 0.25 L
  • Given mass of NaOH = 12 g

Molarity is defined as the number of moles of solute dissolved per litre of solution

Molarity of a solution is calculated by using formula:


{\boxed{\sf {Molarity = (Moles \: of \: solute(mol))/(Volume \: of \: solution(l))}}}

Molar mass of NaOH = 40 g

Calculation for Number of moles:


\sf No. \: of \: moles = (Given \: mass)/(Molar \: mass)


\sf \: No. \: of \: moles = (12)/(40)


\sf No. \: of \: moles = 0.3 \: mol

Hence, The number of moles of solute is 0.3 mol.

Calculating the Molarity:


\sf Molarity = (0.3 \: mol )/(0.25 \: l)


\sf Molarity = 1.2 \: M

Hence, the molarity of the given solution solution is 1.2 M

User Jonathon Chase
by
8.3k points

No related questions found