Question

What is the molarity of a 0.25 L solution containing 12 g of NaOH? Select the correct answer below: 1.2 M 8.6 M 3.4 M 2.8 M

Answer 1

Required Answer:

• the molarity of the solution is 1.2 M

Step-by-step explanation:

We are given with,

• Volume of Solution= 0.25 L
• Given mass of NaOH = 12 g

Molarity is defined as the number of moles of solute dissolved per litre of solution

Molarity of a solution is calculated by using formula:

`{\boxed{\sf {Molarity = (Moles \: of \: solute(mol))/(Volume \: of \: solution(l))}}}`

Molar mass of NaOH = 40 g

Calculation for Number of moles:

`\sf No. \: of \: moles = (Given \: mass)/(Molar \: mass)`

`\sf \: No. \: of \: moles = (12)/(40)`

`\sf No. \: of \: moles = 0.3 \: mol`

Hence, The number of moles of solute is 0.3 mol.

Calculating the Molarity:

`\sf Molarity = (0.3 \: mol )/(0.25 \: l)`

`\sf Molarity = 1.2 \: M`

Hence, the molarity of the given solution solution is 1.2 M