Question

A 2 column by 5 row table. column 1 is titled characteristic and contains the following entries: focal length, distance of object from mirror, distance of image from mirror, height of object. column 2 is titled value and contains the following entries: 13 centimeters, 8 centimeters, negative 21 centimeters, 4 centimeters. what is the height of the image? round the answer to the nearest whole number. cm what type of mirror most likely formed this image?

Answer 1

Explanation:

The height of the image can be determined using the mirror equation, which states:

1/f = 1/d_o + 1/d_i

where f is the focal length of the mirror, d_o is the distance of the object from the mirror, and d_i is the distance of the image from the mirror.

From the given table, we have:

f = 13 cm

d_o = 8 cm

d_i = -21 cm (negative sign indicates that the image is formed on the same side as the object)

Substituting these values into the mirror equation, we get:

1/13 = 1/8 + 1/(-21)

To simplify the equation, we can find the least common denominator (LCD) of 8 and -21, which is 168. Multiplying each term by the LCD, we have:

168/13 = 168/8 - 168/21

Simplifying further, we get:

12.923 = 21 - 8

Therefore, the height of the image is approximately 13 cm (rounded to the nearest whole number).

Based on the given information, the image is formed by a concave mirror. This is because the image distance is negative, indicating that the image is formed on the same side as the object. In a concave mirror, when the object is placed between the focal point and the mirror, the image is virtual, upright, and magnified.