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Idopropanol (c3h8o) is w key ingredient in some hand sanitizers. suppose that 127 grams of isopropanol is dissolved into water. the volume of the solution is 1250 milliliters. what is the molarity of the solution?

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Answer:

Molarity is 1.69M to 3 sig figs

Step-by-step explanation:

Molarity is defined as moles/liter. The question asks us to find the number of moles of C3H8O per liter of water.

First, we need the molar mass of C3H8O. I get 60.0 grams/mole for C3H8O.

Lets now find the number of moles of C3H8O contained in 127 grams of the substance.

moles C3H8O = (127 g)/(60.0 g/mole)

moles C3H8O = (127 g)/(60.0 g/mole)

moles C3H8O = 2.12 moles C3H8O

This amount is dissolved in water to form a final solution volume of 1250 ml. Since there are 1000 ml per liter, we can write 1.250 liters, instead.

The result is that we have 2.22 moles C3H8O in 1.250L. Molar is defined as moles/liter, so we can write:

Molarity = (2.12 moles)/(1.25 L)

Molarity = 1.69M to 3 sig figs

User Rob Donnelly
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