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If 3.5l of a 5.1 m srcl2 solution is diluted to 50l. what is molarity of the diluted solution

1 Answer

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Answer:

SrCl2 is diluted to 0.357M

Step-by-step explanation:

A handy relationship for dilution questions such as this is:

M1*V1 = M2*V2

Where M1 and V2 are the Molarity and Volume of the initial state.

And M2 and V2 are the Molarity and Volume of the final state

Lets collect what we know:

M1 = 5.1M SrCl2

V1 = 3.5L

M2 = Unknown, X

V2 = 50L (!)

Lets rearrange the equation to solve for the unknown, M2:

M2 = (M1V1)/V2

Enter the data and cancel units where possible.

M2 = (M1V1)/V2

M2 = (5.1M)(3.5L)/(50L)

M2 = (5.1M)*(3.5/50) [M cancels]

M2 = (5.1M)*(0.070)

M2 = 0.357M

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