Question

G(x) = x3 6x2 12x 8 a 2-column table with 5 rows. the first column is labeled g of x with entries negative 3, negative 2, 0, 2, 3. the second column is labeled f of x with entries negative 1, 0, 8, 64, 125. determine the function�s value when x = ?1. g(?1) = ?3 g(?1) = 0 g(?1) = 1 g(?1) = 27

Answer 1

Explanation:

I will assume that the equation as written (G(x) = x3 6x2 12x 8) should actually be:

G(x) = x^3 + 6x^2 + 12x + 8

Create the data table with columns x and g(x), which we'll call "y."

y = x^3 + 6x^2 + 12x + 8

I graphed both the points and the equation, mostly to conform that the given points are indeed predicted by the equation. They do: see the attached graph.

With this knowledge, we can find the missing values by entering the one value given and calculating the result.

I'm not clear on the formatting of "when x = ?1. g(?1) = ?3 g(?1) = 0 g(?1) = 1 g(?1) = 27" but will assume the following:

x y

1 ?

? 3

? 0

? 27

If this is correct, here are the results

x y

1 27

`√(3) -2\\` 3

-2 0

1 27