Answer:
47.8 J/(mol·K)
Step-by-step explanation:
To calculate the entropy change (ΔS) for the decomposition of calcium carbonate, we can use the equation:
ΔG = ΔH - TΔS
where ΔG is the change in free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.
Given:
ΔG = 130.5 kJ/mol
ΔH = 178.3 kJ/mol
T = 25.0°C = 298.15 K
We can rearrange the equation to solve for ΔS:
ΔS = (ΔH - ΔG)/T
Substituting the given values, we get:
ΔS = (178.3 - 130.5) kJ/mol / 298.15 K
ΔS = 47.8 J/(mol·K)
Therefore, the entropy change for the decomposition of calcium carbonate is 47.8 J/(mol·K).