Question

12. If APQRASTU, find the value of x.

123 S
5x
Q 22
12
a. 4.4
b. 24.6
RU
c. 7
d. 35
14. Solve using cross multiplication..
20+x
4.5
13. Mildred is flying a kite on a 30 m string. The angle of elevation of the kite measures 40 deg
and Mildred's hand is 2 m above the ground. About how high is the kite off the ground?
a. 21.3 m
c. 19.3 m
d. 23 m
b. 25 m
8

Answer 1

12. answer is 7 option C

13. answer is 21.3m option A

Step-by-step Step-by-step explanation:

question 12

∆pqr and ∆stu are similar triangle

one of the law of similar triangles is they have the same angles

therefore angle p and angle s are equal

angle at p us also 123

sum of angles in a triangle is 180

22 + 123 + y = 180

y = 180 -145

y = 35

angle at u and angle at r are equal

therefore 5x = y

5x = 35

x = 7

question 13

angle of elevation is 40 the string length is 30m and Mildred's hand above ground is 2m

this forms a triangle with extra base of height 2m

the leght is unknown and will be calculated for as x and the hypotenuse is 30m as it's the string of the kite using

sin(40) = opposite/hypotenuse

0.643 = x/30

30 * 0 643 = x

19.29 = x

that's the kite height from the hand of Mildred

the kite height from the ground is now

2 + 19.29 = 21.29

kite height from the ground is ~21.3