Question

Solve using logarithm:
3^(3x-2)=9^(1÷3)

Answer 1

Hello,

Explanation:

Why using logarithm ?

`3^(3x-2)=9^{(1)/(3) }\\\\3^(3x-2)=(3^2)^{(1)/(3) }\\\\3^(3x-2)=3^{(2)/(3)} \\\\3x-2=(2)/(3)\\\\3x=(8)/(3)\\\\x=(8)/(9)`

Answer 2

Answer: x=8/9

Explanation:

3^(3x-2)=3^2(1/3)

3x-2=2/3

3x=8/3

x=8/9