Question

You are given the following substances with their melting and boiling points. Substance Melting Point (0C) Boiling Point (0C) X -219 -183 Y 119 445 Z -15 78 Identify the physical states of X, Y and Z at room temperature (300C).

Answer 1

To identify the physical states of substances X, Y, and Z at room temperature (30°C), we need to compare the given melting and boiling points with the temperature of 30°C.

Substance X:

- Melting Point: -219°C

- Boiling Point: -183°C

At 30°C, which is higher than the boiling point of -183°C for substance X, it would be in a gaseous state.

Substance Y:

- Melting Point: 119°C

- Boiling Point: 445°C

At 30°C, which is lower than the melting point of 119°C for substance Y, it would be in a solid state.

Substance Z:

- Melting Point: -15°C

- Boiling Point: 78°C

At 30°C, which is within the range between the melting point of -15°C and boiling point of 78°C for substance Z, it would be in a liquid state.

Therefore, at room temperature (30°C), substance X would be a gas, substance Y would be a solid, and substance Z would be a liquid.