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Answer:
The area of this trapezoid is
(1/2)(5.7)(7.4 + 2.6) = 5.7(5) = 28.5 cm²
A = 28.5 cm²
Explanation:
the area (A) of a trapezoid is calculated as
A = h (b₁ + b₂)
where h is the perpendicular height between the bases b₁ and b₂
here h = 5.7 , b₁ = 2.6 , b₂ = 7.4 , then
A = × 5.7 × (2.6 + 7.4) = 2.85 × 10 = 28.5 cm²
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