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Answer:
The area of this trapezoid is
(1/2)(6)(7.3 + 2.9) = 3(10.2) = 30.6 mi²
A = 30.6 mi²
Explanation:
the area (A) of a trapezoid is calculated as
A = h (b₁ + b₂ )
where h is the perpendicular height between the bases
here h = 6 , b₁ = 2.9 , b₂ = 7.3 , then
A = × 6 × (2.9 + 7.3 ) = 3 × 10.2 = 30.6 mi²
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