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To solve for θ, subtract 4 from both sides to get −6sinθ = 3√3. Divide both sides by -6 to obtain sinθ = -1√2/2. Use the inverse sine function to find the value of θ. θ = sin^-1(-1√2/2). Simplify the value of θ.
To solve for θ, we will isolate the variable by performing algebraic operations. 1. Subtract 4 from both sides to get −6sinθ = 3√3.2. Divide both sides by -6 to obtain sinθ = -1√2/2.3. Use the inverse sine function to find the value of θ. θ = sin^-1(-1√2/2).4. Simplify the value of θ. θ = -π/4
To solve for θ in the equation -6sinθ+4=3 +4, isolate the term with sinθ, divide by -6 to solve for sinθ, and find the principal angle within the given range of 0≤θ<2π.
To solve for θ in the equation -6sinθ+4=3 +4, we first isolate the term with sinθ by subtracting 4 from both sides: -6sinθ = 3√3. Then, divide both sides by -6 to solve for sinθ: sinθ = (3)/-6 = -. We can use the inverse sine function to find the value of θ: θ = (-).
Since we are given that 0≤θ<2π, we need to find the principal angle whose sine is - within this range. The principal angle in the second quadrant is π/3. Therefore, the solution for θ is θ = π/3.
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