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Find the trigonometric form of tho complex number shown below. −5 3(cos 2/π+tin2/π) b. 5(cos0+tin0) ch. 5(cosπ+isinπ) t. (cos

2/3π+sin 2/3π) cos(cos 4/π+tin 4/π)

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Answer:

a. To find the trigonometric form of the complex number -5 + 3i, we can use the formula r(cosθ + isinθ), where r is the magnitude (distance from the origin) and θ is the argument (angle with the positive real axis).

The magnitude can be found using the Pythagorean theorem:

|z| = √((-5)^2 + 3^2)

|z| = √(25 + 9)

|z| = √34

To find the argument θ, we can use the inverse tangent function:

θ = tan^(-1)(3 / -5)

θ ≈ -0.588 radians

Therefore, the trigonometric form of the complex number -5 + 3i is approximately √34(cos(-0.588) + isin(-0.588)).

b. The complex number 5 can be written as 5(cos0 + isin0) since the magnitude is 5 and the argument is 0 radians.

c. The complex number 5(cosπ + isinπ) can also be written as -5 since the magnitude is 5 and the argument is π radians.

d. The complex number (cos(2/3π) + sin(2/3π)) can be written in trigonometric form as 1(cos(2/3π) + isin(2/3π)).

e. The complex number cos(4/π) + isin(4/π) can be written in trigonometric form as 1(cos(4/π) + isin(4/π)).

Note that in trigonometric form, the magnitude is positive and the argument is within the range of -π to π

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