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Suppose A is an acute angle, and sin A= 4/5, cos A= 3/5

Suppose A is an acute angle, and sin A= 4/5, cos A= 3/5-example-1

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Answer:

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Explanation:


\sin(2A)=2\sin A\cos A=2((4)/(5))((3)/(5))=2((12)/(25))=(24)/(25)


\cos(2A)=\cos^2A-\sin^2A=((3)/(5))^2-((4)/(5))^2=(9)/(25)-(16)/(25)=-(7)/(25)

User Peter Nijem
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