Question

Using the distance formula, d = v(x2-x1)2 + (y2-y)2, what is the distance between point (8, 4) and point (3, 2) rounded to the nearest tenth? 5.4 units 9.2 units O125 units 46 units Skip > 0/10 complete​

Answer 1

d ≈ 5.4 units

Explanation:

calculate the distance d using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = (8, 4 ) and (x₂, y₂ ) = (3, 2 )

d =
`√((3-8)^2+(2-4)^2)`

=
`√((-5)^2+(-2)^2)`

=
`√(25+4)`

=
`√(29)`

≈ 5.4 ( to the nearest tenth )