Question

4)

AACE ~ AIKS
Find x and y
I
Y
K
4
S
X
E
8
C
7
A
12

Answer 1

8/4 = 2

12/x = 2---->x = 6

7/y = 2----->y = 3.5

Answer 2

x = 6 , y = 3.5

Explanation:

since the triangles are similar then the ratios of corresponding sides are in proportion , that is

`(IS)/(AE)` =
`(KS)/(CE)` ( substitute values )

`(x)/(12)` =
`(4)/(8)` ( cross- multiply )

8x = 12 × 4 = 48 ( divide both sides by 8 )

x = 6

and

`(IK)/(AC)` =
`(KS)/(CE)` ( substitute values )

`(y)/(7)` =
`(4)/(8)` ( cross- multiply )

8y = 7 × 4 = 28 ( divide both sides by 8 )

y =
`(28)/(8)` = 3.5