Question

In a sealed and rigid container, a sample of gas at 4. 40 atm and 25. 0 °C is heated to 50. 0 °C. What is the pressure (in atm) of the gas at 50. 0 °C?

Answer 1

Answer: 36.90 atm

Step-by-step explanation:

P1V1 = P2V2 (Boyles Law)

25 C = 298K 50 C = 323K

(40atm)(298K) = (323K) (P)

P = (40atm)(298K) / (323K)

P = 36.90 atm