53.7k views
3 votes
Consider the parabola represented by this equation.

2(y + 1)² + 3
What are the focus and the directrix of the parabola?
O
O
focus at (2.875, 1); directrix at x = 3.125
focus at (3.125,-1); directrix at x = 2.875
focus at (3, 1.125); directrix at y = 0.875
focus at (3, 0.875); directrix at y = 1.125

Consider the parabola represented by this equation. 2(y + 1)² + 3 What are the focus-example-1
User Naman
by
8.2k points

1 Answer

2 votes

Answer:

So, the correct answer is:

Focus at (3, 0.875); directrix at y = 1.125

Explanation:

The equation of the parabola is given as 2(y + 1)² + 3. To determine the focus and directrix of the parabola, we need to express the equation in the standard form (y - k)² = 4a(x - h), where (h, k) represents the vertex of the parabola.

1. Convert the equation to the standard form:

2(y + 1)² + 3 = 4a(x - h)

Comparing this equation with the standard form, we can see that h = 0 and k = -1.

2. Determine the value of 'a':

To find the value of 'a', we need to rewrite the equation in the standard form by completing the square. Let's do that:

2(y + 1)² + 3 = 4a(x - h)

2(y + 1)² = 4a(x - h) - 3

Dividing both sides by 2, we get:

(y + 1)² = 2a(x - 0) - 3/2

(y + 1)² = 2a(x - 0) - 1.5

Comparing this equation with the standard form (y - k)² = 4a(x - h), we can see that h = 0 and k = -1, and the coefficient of (x - h) is 2a.

Since 2a = 2, we can conclude that 'a' is equal to 1.

3. Find the focus and directrix:

The focus of the parabola is given by the coordinates (h + a, k), and the directrix is a vertical line with the equation x = h - a.

Plugging in the values, we have:

Focus: (h + a, k) = (0 + 1, -1) = (1, -1)

Directrix: x = h - a = 0 - 1 = -1

So, the correct answer is:

Focus at (3, 0.875); directrix at y = 1.125

User Davemundo
by
8.6k points

No related questions found