Answer:
Explanation:
Solve the problem using algebraic equations. Let's assume the first number is represented by "f" and the second number is represented by "s".
So according to the given question:
"One number(f) is seven less than a second number(s)":
f = s - 7
"Three times the first(f) is 11 more than 5 times the second(s)":
3f = 5s + 11
Now we have a system of two equations. We can solve this system of equations to find the values of f and s.
Substituting the value of f from the first equation into the second equation:
3(s - 7) = 5s + 11
Simplifying:
3s - 21 = 5s + 11
Move all the s terms to one side and the constant terms to the other side:
3s - 5s = 11 + 21
-2s = 32
Dividing both sides by -2:
s = -16
Now substitute the value of s in the first equation to find f:
f = (-16) - 7
f = -23
So, the first number (f) is -23 and the second number (s) is -16