230k views
0 votes
Suppose you have $3000 to invest. Which investment yields the greater return over 10 years: 6.5% compounded semiannually or 6% compounded continuously? How much more (to the nearest dollar ) is yielded by the better investment?

2 Answers

3 votes

Final answer:

The second investment, which yields a 6% interest rate compounded continuously, has a higher future value compared to the first investment, which yields a 6.5% interest rate compounded semiannually. The difference in yield between the two investments is $115.76.

Step-by-step explanation:

To compare the two investments, we need to calculate the future value of each investment after 10 years.

For the first investment, which yields a 6.5% interest rate compounded semiannually, we can use the formula:

FV = P(1 + r/n)^(nt)

Where FV is the future value, P is the principal amount, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years.

For the second investment, which yields a 6% interest rate compounded continuously, we can use the formula:

FV = Pe^(rt)

Where e is the base of the natural logarithm.

Calculating the future value of each investment:

For the first investment:

  1. Principal amount (P) = $3000
  2. Annual interest rate (r) = 6.5%
  3. Number of times compounded per year (n) = 2 (semiannually)
  4. Number of years (t) = 10

Using the formula:

FV = 3000(1 + 0.065/2)^(2*10)

Calculating the future value:

FV ≈ $5085.53

For the second investment:

  1. Principal amount (P) = $3000
  2. Annual interest rate (r) = 6%
  3. Number of years (t) = 10

Using the formula:

FV = 3000e^(0.06*10)

Calculating the future value:

FV ≈ $5201.29

The second investment, which yields a 6% interest rate compounded continuously, has a higher future value of approximately $5201.29, compared to the first investment with a future value of approximately $5085.53.

The difference in yield between the two investments is approximately $5201.29 - $5085.53 = $115.76.

User ErikR
by
7.3k points
7 votes

Final answer:

For Investment A with a 6.5% interest compounded semiannually, the future value is $5377.98. For Investment B with a 6% interest compounded continuously, the future value is $5417.18. The better investment yields approximately $39.20 more.

Step-by-step explanation:

To compare which investment yields the greater return over 10 years, we need to calculate the future value using compound interest.

Investment A: 6.5% compounded semiannually

The formula for calculating compound interest is:


A = P(1 + r/n)^(nt),

where A is the future value, P is the initial principal, r is the annual interest rate, n is the number of compounding periods per year, and t is the number of years.

For Investment A: P = $3000, r = 0.065, n = 2 (semiannually compounded), and t = 10. Plugging in these values, we get:


A = $3000(1 + 0.065/2)^(2*10)

= $5377.98

Investment B: 6% compounded continuously

The formula for calculating continuous compound interest is:


A = Pe^(rt), where e is Euler's number (approximately 2.71828).

For Investment B: P = $3000, r = 0.06, and t = 10. Plugging in these values, we get:


A = $3000 * e^(0.06*10)

= $5417.18

Subtracting the initial investment, the better investment yields approximately $39.20 more (rounded to the nearest dollar).

User Frifle
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories