Answer:
Expressed as a function of x10^-25, E = 578 J, to 3 sig figs
Step-by-step explanation:
E=hv
where
E is energy, in Joules
h is Plank's constant of 6.626x10^-34 J-s
and v is frequency, in s^-1
We are given wavelength (0.344 m), but need frequency (s^-1). Use the relationship:
c = wv, where c is the speed of light and w is wavelength.
3x10^6 m/s = (0.344 m)*v
v = 8720930 or 8.721x10^6 s^-1
Now we can calculate E:
E = (6.626x10^-34 J-s)*(8.721x10^6 s^-1)
E = 5.778 x 10^-27 J
Expressed as a function of x10^-25, this is
E = 578 J, to 3 sig figs
[The wavelength0.344 meters seems high, but it provides an answer close to that predicted in the question. Electromagnetic waves are generally expressed in nanometers, not m. So this must be a very low energy signal.