Main Answer:
a) The subnet mask in CIDR notation is /29.
b) The broadcast address of the 6th subnet is 57.156.223.191.
c) The 1st host of the 9th subnet is 57.156.223.193 and the last host is 57.156.223.198.
Step-by-step explanation:
To solve the given question, we need to determine the subnet mask in CIDR notation, find the broadcast address of the 6th subnet, and identify the 1st and last host of the 9th subnet for the given IP address 57.156.223.185.
a) Subnet Mask in CIDR notation:
When 7 bits are used to create subnets, it means that we have 2^7 (128) subnets available. To determine the subnet mask in CIDR notation, we need to count the number of bits used for the subnets. In this case, 7 bits are used, so the subnet mask can be represented as /29. The number after the slash denotes the number of bits used for the network portion of the IP address.
b) Broadcast address of the 6th subnet:
To calculate the broadcast address of a subnet, we need to determine the network address and the subnet mask. Since the 6th subnet is being considered, we can calculate the network address by adding 6 times the subnet size to the base network address. With a /29 subnet mask, the subnet size is 8 (2^(32 - 29)). Thus,