To determine the volume of Oz gas required to react with CO gas, we need to balance the chemical equation first. The balanced equation for the reaction between CO and O2 to produce CO2 is:
2 CO + O2 -> 2 CO2
According to the balanced equation, 2 moles of CO react with 1 mole of O2 to produce 2 moles of CO2. Since we know the volume of CO gas (3.02 L) at STP, we can use the molar volume of a gas at STP (22.4 L/mol) to calculate the number of moles of CO:
moles of CO = volume of CO gas / molar volume at STP
= 3.02 L / 22.4 L/mol
= 0.135 mol
From the balanced equation, we know that 2 moles of CO react with 1 mole of O2. Therefore, with 0.135 mol of CO, we would need half as much O2:
moles of O2 = 0.135 mol / 2
= 0.0675 mol
Finally, we can calculate the volume of O2 gas using the molar volume at STP:
volume of O2 gas = moles of O2 * molar volume at STP
= 0.0675 mol * 22.4 L/mol
= 1.51 L
Therefore, the volume of O2 gas required to completely react with 3.02 L of CO gas at STP is approximately 1.51 L.