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Find the oxidation number of: > A. nitrogen in N2H4 B. iron in Fe2+ C.

User Babasaheb
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Sure! Let's find the oxidation number of each element you mentioned:

A. To find the oxidation number of nitrogen in N2H4, we need to know that the overall charge of the molecule is zero. Since hydrogen is typically assigned an oxidation number of +1 and there are four hydrogens in N2H4, their total contribution would be +4. Therefore, the oxidation number of nitrogen can be calculated as follows:
2(N) + 4(H) = 0
2(N) + 4(+1) = 0
2(N) + 4 = 0
2(N) = -4
(N) = -2
So, the oxidation number of nitrogen in N2H4 is -2.

B. To find the oxidation number of iron in Fe2+, we know that the overall charge of the ion is +2. Therefore, the oxidation number of iron is +2.
User Federico Ojeda
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