Optimize f(x) = 2x ^ 2 - 30x ^ 2 + 12x + 59 Find the critical points by taking the first derivative, setting it equal to zero, and solving for x

asked Feb 8, 2024 168k views

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Optimize f(x) = 2x ^ 2 - 30x ^ 2 + 12x + 59 Find the

critical points by taking the first derivative, setting it equal to
zero, and solving for x

8.9k points

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3 votes

Answer:

x = 3/14

Explanation:

$f(x)=2x^2-30x^2+12x+59\\f(x)=-28x^2+12x+59\\f'(x)=-56x+12\\\\0=-56x+12\\-12=-56x\\(3)/(14)=x$

Therefore, x=3/14 is a critical point

Idoimaging answered Feb 15, 2024

8.2k points

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