Question

The vertices of a rhombus are located at (a, 0), (0, b), (-a, 0), and (0, -b). What is the midpoint of the side that is in quadrant II? O (-a/2, b/2) O (a/2, b/2) O (a, b) O (0,0)​

Answer 1

Answer: (-a/2, b/2)

Explanation:

We know that in the second quadrant, the x values are always negative and the y values are always positive. This means that the points of the side in the second quadrant are : (-a, 0) and (0,b). Then we can find the midpoint:

((-a+0)/2,(b+0)/2)

= (-a/2,b/2)