Determine a value for s so that f(x)=sx^2−5x−2 has a minimum at x=5 s=_____?____

asked Jul 12, 2024 229k views

5 votes

Determine a value for s so that f(x)=sx^2−5x−2 has a minimum at x=5

s=_____?____

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3 votes

Answer:

f(x) = sx² - 5x - 2

f'(x) = 2sx - 5

f'(5) = 10s - 5 = 0

10s = 5

s = 1/2

Dejay answered Jul 18, 2024