229k views
5 votes
Determine a value for s so that f(x)=sx^2−5x−2 has a minimum at x=5

s=_____?____

User HimanshuR
by
8.8k points

1 Answer

3 votes

Answer:

f(x) = sx² - 5x - 2

f'(x) = 2sx - 5

f'(5) = 10s - 5 = 0

10s = 5

s = 1/2

User Dejay
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories