Answer: x-component will be close to 64.7N. y-component will be close to 47N
Explanation: Let the force exerted on the bag be F, where |F|=80N
x-component of the force will be parallel to the ground.
Therefore, the x-component of the force F will be |F|cos36°
--> 80cos36°
--> 80* 0.80901699437
--> 64.7 (approximately)
y-component of the force F will be perpendicular to the ground.
Therefore, the y-component of the force F will be |F|cos(90°-36°)
--> 80sin36° {cos(90°-x)=sinx}
--> 80* 0.58778525229
--> 47 (approximately)