Question

Suppose that an ethane molecule, CH_3CH_3, is broken into two CH_3 molecules in such a way that one :CH_3 molecule (molecule A) retains the electron pair that was originally the one making up the C-C bond. The other CH_3 molecule (molecule B) has two fewer electrons. Now, select the correct statement from the list:

a) Both molecules have trigonal planar geometry.
b) Molecule A has trigonal pyramidal geometry and molecule B has planar trigonal geometry.
c) Molecule A has tetrahedral geometry and molecule B has planar trigonal geometry.
d) Both molecules have trigonal pyramidal geometry.

Answer 1

In the original ethane molecule (CH3CH3), the carbon atoms are bonded to each other by a single C-C bond. Each carbon atom is also bonded to three hydrogen atoms, resulting in a tetrahedral geometry around each carbon atom.

When the ethane molecule is broken into two CH3 molecules, one of the CH3 molecules (molecule A) retains the electron pair that was originally the C-C bond. As a result, this molecule (A) still maintains the tetrahedral geometry around the carbon atom.

On the other hand, the other CH3 molecule (molecule B) has two fewer electrons since it lost the electron pair that formed the C-C bond. This leads to a loss of one of the bonds and the geometry becomes planar trigonal. In a planar trigonal geometry, the carbon atom is bonded to only two hydrogen atoms and does not have a bond in the place where the C-C bond was broken

Answer 2

d

Step-by-step explanation:

i had to do this on oddesyware and i picked this one and got it right