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For a Buck DC-DC converter Vin=10V, V=5V, f=100kHz, L=4.1uH, C=376uF, Rload=192 Calculate AV. (peak-peak) for the converter?

User Xaviera
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1 Answer

5 votes

Answer:

To calculate the peak-to-peak voltage (AV) for a Buck DC-DC converter, we can use the following formula:

AV = (Vin - V) / (2 * pi * f * L * Iload)

Where:

- Vin is the input voltage, which is 10V in this case.

- V is the output voltage, which is 5V.

- f is the switching frequency, which is 100kHz.

- L is the inductance, which is 4.1uH.

- Iload is the load current, which we need to calculate.

To calculate Iload, we can use the formula:

Iload = V / Rload

Where:

- V is the output voltage, which is 5V.

- Rload is the load resistance, which is 192 ohms.

Substituting the values into the formula:

Iload = 5V / 192 ohms = 0.026A (approximately)

Now, we can substitute the values into the first formula to calculate AV:

AV = (10V - 5V) / (2 * pi * 100kHz * 4.1uH * 0.026A)

Note: To calculate with microhenries and microfarads, we need to convert them to henries and farads respectively:

4.1uH = 4.1 * 10^(-6) H

376uF = 376 * 10^(-6) F

Calculating AV:

AV = (10V - 5V) / (2 * pi * 100kHz * 4.1 * 10^(-6) H * 0.026A)

= 5V / (2 * 3.1416 * 100,000Hz * 4.1 * 10^(-6) H * 0.026A)

= 5V / (0.01623)

= 307.88V (approximately)

Therefore, the peak-to-peak voltage (AV) for the Buck DC-DC converter is approximately 307.88V.

User Firebitsbr
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