Answer:
To calculate the peak-to-peak voltage (AV) for a Buck DC-DC converter, we can use the following formula:
AV = (Vin - V) / (2 * pi * f * L * Iload)
Where:
- Vin is the input voltage, which is 10V in this case.
- V is the output voltage, which is 5V.
- f is the switching frequency, which is 100kHz.
- L is the inductance, which is 4.1uH.
- Iload is the load current, which we need to calculate.
To calculate Iload, we can use the formula:
Iload = V / Rload
Where:
- V is the output voltage, which is 5V.
- Rload is the load resistance, which is 192 ohms.
Substituting the values into the formula:
Iload = 5V / 192 ohms = 0.026A (approximately)
Now, we can substitute the values into the first formula to calculate AV:
AV = (10V - 5V) / (2 * pi * 100kHz * 4.1uH * 0.026A)
Note: To calculate with microhenries and microfarads, we need to convert them to henries and farads respectively:
4.1uH = 4.1 * 10^(-6) H
376uF = 376 * 10^(-6) F
Calculating AV:
AV = (10V - 5V) / (2 * pi * 100kHz * 4.1 * 10^(-6) H * 0.026A)
= 5V / (2 * 3.1416 * 100,000Hz * 4.1 * 10^(-6) H * 0.026A)
= 5V / (0.01623)
= 307.88V (approximately)
Therefore, the peak-to-peak voltage (AV) for the Buck DC-DC converter is approximately 307.88V.