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Consider the following pn junction at room temperature (300 K).

N_A= 2.5E+18/cm³
N_D=7.0E+16/cm³
Find the boundary of the depletion layer in the n-region, Xn
Useful constants:
k = 8.62E-05
q=1.60E-19
∈_si =11.8
∈_0=8.85E-14

User Gymbrall
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To find the boundary of the depletion layer in the n-region (Xn) of a pn junction at room temperature, we can use the following formula:

Xn = sqrt((2 * ε_si * (Vbi + VR))/(q * (1/N_A + 1/N_D)))

Where:
- Xn is the boundary of the depletion layer in the n-region
- ε_si is the permittivity of silicon (11.8 in this case)
- Vbi is the built-in voltage
- VR is the reverse bias voltage
- q is the charge of an electron (1.60E-19 Coulombs)
- N_A is the acceptor concentration
- N_D is the donor concentration

Now, let's calculate the values needed to find Xn:

Step 1: Calculate the built-in voltage (Vbi)
Vbi = (k * T/q) * ln(N_A * N_D / ni^2)

Where:
- k is the Boltzmann constant (8.62E-05 eV/K)
- T is the temperature in Kelvin (300 K)
- ni is the intrinsic carrier concentration

Step 2: Calculate the intrinsic carrier concentration (ni)
ni = sqrt(N_C * N_V) * exp(-Eg / (2 * k * T))

Where:
- N_C is the effective density of states in the conduction band
- N_V is the effective density of states in the valence band
- Eg is the energy gap of silicon (1.12 eV)

Step 3: Calculate the reverse bias voltage (VR)
VR = 0 (since we are considering no reverse bias)

Step 4: Substitute the values into the formula for Xn

Xn = sqrt((2 * 11.8 * (Vbi + VR))/(1.60E-19 * (1/2.5E+18 + 1/7.0E+16)))

Now, let's calculate each step in detail:

Step 1: Calculate Vbi
Vbi = (8.62E-05 * 300)/1.60E-19 * ln((2.5E+18 * 7.0E+16)/(1.5E10)^2)
Vbi = 0.714 V

Step 2: Calculate ni
ni = sqrt(2.8E19 * 1.04E19) * exp(-1.12/(2 * 8.62E-05 * 300))
ni = 9.65E9/cm³

Step 3: Calculate VR
VR = 0

Step 4: Calculate Xn
Xn = sqrt((2 * 11.8 * (0.714 + 0))/(1.60E-19 * (1/2.5E+18 + 1/7.0E+16)))
Xn = 4.77E-5 cm

Therefore, the boundary of the depletion layer in the n-region (Xn) is approximately 4.77E-5 cm.

Main answer: The boundary of the depletion layer in the n-region (Xn) is approximately 4.77E-5 cm.

Explanation: To find Xn, we use the formula Xn = sqrt((2 * ε_si * (Vbi + VR))/(q * (1/N_A + 1/N_D))). We first calculate the built-in voltage (Vbi) using the formula Vbi = (k * T/q) * ln(N_A * N_D / ni^2). Then, we calculate the intrinsic carrier concentration (ni) using the formula ni = sqrt(N_C * N_V) * exp(-Eg / (2 * k * T)). Finally, we substitute the values into the formula for Xn and calculate it.

User Binaya
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