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What is the molar mass of Lead (IV) nitrate? (no units needed in answer just numbers to the the hundredth place)

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Answer:

It's 455.24

Step-by-step explanation:

Lead (IV) Nitrate is Pb(NO3)4. We check the periodic table for each of the element's molar mass. So lead is 207.2 g/mol, nitrogen is 14 g/mol and oxygen is 16 g/mol. We will have the equation of lead nitrate's molar mass that is:

207.2 + (14 + 16×3)×4 = 455.24 g/mol

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