Answer:
It's 455.24
Step-by-step explanation:
Lead (IV) Nitrate is Pb(NO3)4. We check the periodic table for each of the element's molar mass. So lead is 207.2 g/mol, nitrogen is 14 g/mol and oxygen is 16 g/mol. We will have the equation of lead nitrate's molar mass that is:
207.2 + (14 + 16×3)×4 = 455.24 g/mol