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the sum of 4 different odd integers is 64. what is the value of the greatest of these integers? the integers are consecutive odd numbers. of these integers, the greatest is 6 more than the least.

User Manixrock
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2 Answers

2 votes

Answer:

Explanation:

let x is the first odd number

x + 2 is the second odd number

x + 4 is the third odd number

x + 6 is the fourth number

Just add all of them

x + x + 2 + x + 4 + x + 6 = 64

4x + 12 = 64

4x = 52

x = 13 first number

x + 2 is 13 + 2 = 15 second number

x + 4 is 13 + 4 = 17 third number

x + 6 is 13 + 6 = 19 fourth number

19 is the greatest

19 is 6 more than 13

User Mahooresorkh
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8.3k points
4 votes

Answer:

19

Explanation:

You want the largest of four consecutive odd integers that have a sum of 64.

Average

The mean value of those integers is 64/4 = 16. This is the even number between the middle two odd integers. That means the four integers are ...

13, 15, 17, 19

The greatest of the integers is 19.

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Additional comment

You can write equations for problems like this, but it is often easy to do the arithmetic mentally by considering the average of the consecutive numbers.

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User Kurtko
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