Question

What is the equation of an oblique line with a slope = 6 and passing through the point (0, 3)?

Answer 1

Equations

Subsitute the data into y = mx + c.

y = 6x + c (6 is our slope)

3 = 6(0) + c

3 = 0 + c

3 = c

The equation is calculated as y = 6x + 3.

Answer 2

y = 6x + 3

Explanation:

The equation of a line in point-slope form is:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, and m is the slope of the line.

Substituting the given values, we have:

y - 3 = 6(x - 0)

Simplifying the right-hand side:

y - 3 = 6x

Bringing the constant term to the right-hand side:

y = 6x + 3