Question

the area of a triangular flag is 132 square centimeters. It's altitude is 2 centimeters longer than twice it's base. Find the lengths of the altitude and the base

Answer 1

Height/Altitude is 24 centimeters

Base is 11 centimeters

Explanation:

`132=(bh)/(2)\\h=2b+2\\\\132=(b(2b+2))/(2)\\132=(2b^2+2b)/(2)\\132=b^2+b\\0=b^2+b-132\\0=(b+12)(b-11)\\b=11,-12`

Since the length of the base can't be negative, then the correct base would be 11 centimeters. This makes the altitude
`h=2(11)+2=22+2=24`.