128k views
5 votes
PLEASE PLEASE PLEASE HELP ASAP

Graph g(x) = |x − 3|.

A. The graph shows an upward opening v-shaped graph with a vertex at negative 3 comma 0, which passes through negative 4 comma 1 and negative 2 comma 1.

B. The graph shows an upward opening v-shaped graph with a vertex at 3 comma 0, which passes through 2 comma 1 and 4 comma 1.

C. The graph shows an upward opening v-shaped graph with a vertex at 0 comma 3, which passes through negative 1 comma 4 and 1 comma 4.

D. The graph shows an upward opening v-shaped graph with a vertex at 0 comma negative 3, which passes through negative 1 comma negative 2 and 1 comma negative 2.

2 Answers

4 votes

Answer: B

Explanation:

g(x) = |x − 3|

has a vertex at (3,0)

and

does pass through

(2,1) and (4,1)

just like what B says.

"B. The graph shows an upward opening v-shaped graph with a vertex at 3 comma 0, which passes through 2 comma 1 and 4 comma 1."

PLEASE PLEASE PLEASE HELP ASAP Graph g(x) = |x − 3|. A. The graph shows an upward-example-1
User Allenh
by
8.1k points
7 votes

Answer:

B

Explanation:

The absolute value parent function is y=|x|

g(x) can also be written as y.

y=|x-3|

This graph shifts 3 units to the right. The vertex is (3,0) because when you plug 3 as x into the equation; y=|3-3| you get y=0

When 2 is plugged into the equation

y=|2-3|

2-3=-1

y=|-1|

y=1 when x is 2

When 4 is plugged into the equation

y=|4-3|

4-3=1
y=|1|

y=1 when x is 4

A graph is attached for a visual.

PLEASE PLEASE PLEASE HELP ASAP Graph g(x) = |x − 3|. A. The graph shows an upward-example-1
User Pelshoff
by
9.4k points

No related questions found