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A business firm has 800 employees out of which 176 are married men, 272 are married women, 208 are single men, and
144 are single women. Letz- 0, 1, 2 and 3 represent the events that a person is a married man, married woman, single
man and single woman, respectively. Find the probability distribution. Arrange z in increasing order and write the
probabilities P(x) as simplified fractions.
Provide your answer below:
X
P(x)
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User Edisson
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To find the probability distribution for the events of being a married man (0), married woman (1), single man (2), and single woman (3), we need to calculate the probabilities for each event.

Given the following information:

- Number of married men (0): 176
- Number of married women (1): 272
- Number of single men (2): 208
- Number of single women (3): 144

Total number of employees: 800

We can calculate the probabilities as follows:

P(0) = Number of married men / Total number of employees = 176 / 800 = 22 / 100 = 11 / 50
P(1) = Number of married women / Total number of employees = 272 / 800 = 34 / 100 = 17 / 50
P(2) = Number of single men / Total number of employees = 208 / 800 = 26 / 100 = 13 / 50
P(3) = Number of single women / Total number of employees = 144 / 800 = 18 / 100 = 9 / 50

Now, we can arrange the probabilities (P(x)) in increasing order:

X | P(x)
---------------
0 | 11/50
2 | 13/50
3 | 9/50
1 | 17/50

The probability distribution, arranged in increasing order of events (z), is as follows:

X | P(x)
---------------
0 | 11/50
2 | 13/50
3 | 9/50
1 | 17/50
User Shihab Uddin
by
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