Question

Consider the difference equation k)+0.1y(k−1)+0.2y(k−2)−0.1y(k−3)+2y(k−4)=u(k−2)+0.1u(k−3 z

1 =0.5 z 2=−0.5 z 3=−0.2+0.5i z 4 =−0.2−0.5i

Answer 1

The difference in this equation is that xy + xz gets published